OK, I'll bite...
Measurements were:
Across R8: 926K
Across R9: 770K
Across R10: 443K
Let the three resistors of the star be Ra Rb and Rc.
Ra+Rb = 926K (
Eq1)
Ra+Rc = 770K (
Eq2)
Rb+Rc = 443K (
Eq3)
Rearranging
Eq3 we have:
Rb = 443K - Rc
Substituting for Rb in
Eq1 we have:
Ra + 443K - Rc = 926K
Simplifying:
Ra - Rc = 483K
Adding this to
Eq2 we have:
2 Ra + Rc - Rc = 483K + 770K
so:
Ra = 626.5K
Therefore Rb = 299.5K and Rc = 143.5K.
Now for the star to delta conversion...
Let Z be (Ra x Rb) + (Ra x Rc) + (Rb x Rc)
Z = 320517.75 x 10^9
R8 = Z / Rc ~= 2233.6K
R9 = Z / Rb ~= 1070.2K
R10 = Z / Ra ~= 511.6K
QED (quite easily done
)