You can't do what I think you are doing, it won't work as expected.
To get any useful output the anode should be at about the same voltage as g2+g4, probably a bit higher even.
So if you have a resistor to the anode, you also need one for g2+g4, pin 6, and then regulate the voltage to the whole thing.
The reason why the original circuit worked without any resistor to g2+g4 was that the DC voltage drop across the tuned circuit was close to zero.
At 150V supply voltage you need 10 + 10->15K for the anode as described previously, and 10K as voltage dropper for g2+g4. That should give you something like 100V on both pin 5 and 6 if the valve operates somewhat close to normal. Pin 5 now ought to have the sine voltage signal superimposed on the DC voltage. Use a DC blocking capacitor from the anode and to the scope to see the AC signal.
Edit:
Quote:
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Originally Posted by adibrook
I presume that these extra resistors are to make lower voltage?
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That plus ensuring a similar voltage on both pin 5 and 6 in the presense of the anode load resistor.