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kalee20 · 21st Jan 2021, 9:37 pm

If the peak-to peak current is 1A, and the retrace time 7μsec, then current is changing at the rate of dI/dt = 1A/7μsec = 143,000 A/sec.

Now the defining equation for inductance is given by V = L x dI/dt.

Putting in the numbers, with L = 10mH, we get voltage = 1,430V or not far off the 1.5kV they claim.

Hope that helps!

21st Jan 2021, 9:37 pm	#2
kalee20 Dekatron Join Date: Feb 2007 Location: Lynton, N. Devon, UK. Posts: 7,088	Re: Question on a bit of theory If the peak-to peak current is 1A, and the retrace time 7μsec, then current is changing at the rate of dI/dt = 1A/7μsec = 143,000 A/sec. Now the defining equation for inductance is given by V = L x dI/dt. Putting in the numbers, with L = 10mH, we get voltage = 1,430V or not far off the 1.5kV they claim. Hope that helps!