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Old 26th Apr 2018, 10:50 am   #1
Brian of Romsey
Triode
 
Join Date: Jul 2017
Location: Fairfield, Melbourne, Australia
Posts: 48
Default Pin-out for SEI Quartz Oscillator

Hi,

I realise this might be a bit off-topic, but I'm hoping that this is the right audience.

I have recently acquired an SEI brand quartz oscillator about which I'm hoping to get some information on the pin-out and the supply voltage. It is labelled as follows (with the bold text hand written onto the label):
SEI QUARTZ OSCILLATOR
QC. 1260
PART No.
FREQUENCY 94.808 MHz

SERIAL No. 721559
MADE IN ENGLAND
The case is 1.4" by 1.0", and about 0.4" thick. On the bottom there are four pins in a rectangle 1.0" by 0.5". One of the pins is clearly ground and is directly connected to the case, the other three are isolated. Below is a poor diagram showing the layout:

Code:
------------------
|  A          B  |
|                |
|  G          C  |
------------------
With G being the ground pin and A, B, & C being the other three. Pins G, B, & C show signs of having been soldered to in the past, pin A looks clean in this respect.

So, any suggestions about pin-out or supply voltage? I'm guessing that it will be a 5 Volt part with a full swing on the output, maybe TTL-like.

Thanks in Advance, Brian.
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