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Old 14th Nov 2017, 4:00 pm   #6
kalee20
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Join Date: Feb 2007
Location: Lynton, N. Devon, UK.
Posts: 7,081
Default Re: Transcendental magic: Schade's peak voltage equation and my discovery!!

For large values of Q, the amplitude of oscillation in an LC circuit hardly decays between one cycle and the next.

The ratio of successive peaks is actually e^(-pi/Q) which is 97% for Q=100; 99.4% for Q=500; etc.

But, we're not looking at the relationship between one cycle and the next; we're looking at the relationship between maximum current and maximum voltage. And these occur, 1/4 cycle apart. So during this time the exponential decay has only kicked in for 1/4 of the time, and this explains why the exponential term in your equation is e^(-pi/4Q).

With so little decay, the error in neglecting the exponential term is, for most purposes, peanuts! So, the Q=100 case gives you, as you say, 0.9921 as a multiplier. So if you neglect it, you get an error of 0.78% in peak voltage, not very much! In fact, the % error is approximately 25 x pi/Q, or just 78/Q percent!
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