So I reckon each 'tick' on the horizontal line in the middle of the display is whatever the time/div setting is, so with that set to 50ms, I can see c. 13.5 ticks = 675ms.
I reckon each pulse is 12.5 * 50 = 575ms
If each dotted horizontal line is equal to the vertical voltage setting, then that's 2 x 2.0V = 4V
Have I got that right?
Colin.
Quote:
Originally Posted by SiriusHardware
Yes, the ability to 'pan' left and right can be useful.
I'm going to let Mark go with this for a while so you don't get conflicting instructions sending you in two directions at once.
In the meantime a little exercise for you:
Taking your screen shot in #680,
Can you say, roughly...
How many milliseconds there are between the falling edge of the first _CE pulse and the falling edge of the second _CE pulse?
How long (In milliseconds) is one _CE pulse?
Assuming the low edges of the _CE pulses are at 0V, what voltage is the _CE line at when it is NOT low?
(With the scope settings as they were, each horizontal division is 50mS: Each vertical division is 2V).
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