[ms660]

Re: Post#204....Maths isn't my strong point either but here goes (only done to four decimal points):

If that's the oscillator waveform then looking at the 'scope screen starting with the second +ve peak from the right hand side gives 13 complete time periods over 7 divisions, that equals 1.8571 periods per division (13/7)

That's with x5 magnification, so at x1 magnification it would equal 9.2855 time periods per division (5*1.8571)

Continuing with the x1 deduction figure:

The 'scopes timebase is set to 10us per division, so that means there's 9.2855 time periods per 10us, that means a single time period is 1.0769us (10/9.2855)

The frequency in mHz equals 1/t (t = the time period in microseconds) therefore the frequency equals 1/1.0769 which equals .9285 mHz which is 928.5 kHz.

Assuming the IF's are in proper alignment the IF will be 465 kHz, so the RF would need to be tuned to 928.5 kHz minus 465 kHz which is 463.5 kHz.

So based on the above, the oscillator frequency is too high for reception on 1500 meters.

If I've got that right, see what the rest of the gang think.

This post might cross.

Lawrence.