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Old 1st Apr 2019, 2:15 pm   #60
DonaldStott
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Join Date: Aug 2015
Location: Glasgow, UK.
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Default Re: Turntable Stroboscope

I've taken a step back as I was getting my frequencies, duty cycles, asserted signals and other concepts confused - so bear with me but please BUZZ when you see an incorrect step!

We currently have a 300 Hz symmetrical square wave so the duty cycle is 50%

At 300 Hz the time interval is given by 1/300 = 0.003333 seconds = 3333 microseconds.

So within this 3333μs period we have 1666.5μs of asserted signal, followed by 1666.5μs of deasserted signal i.e. 50% duty cycle.

Ideally we want the LED to be on 1/16th of the time which is 3333μs divided by 16 (or multiplied by 0.0625) = 208.3125μs.

6.25% duty cycle and an asymmetric square wave ??

So far, so good ...?

How do we then calculate the circuity needed e.g. resistors and capacitors, to produce the necessary input for a 5555 monostable mode circuit??
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Last edited by DonaldStott; 1st Apr 2019 at 2:26 pm.
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