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Old 25th Jun 2007, 7:13 pm   #8
daviddeakin
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Join Date: Apr 2007
Location: W Yorks, UK.
Posts: 407
Default Re: making of a triode coupled RIAA preamp

Quote:
Originally Posted by oldeurope View Post
I can not see another way than the "red line" for the signal flow.
Never mind. I was really arguing that because all current, (AC or DC) is suppled by the power supply, there is no such thing as a "siganl path", since ALL components are involved with the flow of current. It's not important.

I have been looking more closely at the theory. You say the AC signal through the tride transformer is divided my mu. This is not so; the AC signal gain through it can be given by:
Av= (ra + Ra) / ra

where:
ra = triode internal impedance
Ra = load resistance (R10 / R20)

To minimise signal loss, it is therefore desirable to make ra large, and Ra small. One method of making ra large would be to use a pentode, but that adds complexity. Another method would be to lower the heater voltage. This will considerably increase ra for a given bias voltage, but also increase linearity!

I still do not see a reason for V1, when you could input the signal directly to the grid of V2, thereby eliminating distortion caused by V1?
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